1
AIEEE 2009
MCQ (Single Correct Answer)
+4
-1
A charge $$Q$$ is placed at each of the opposite corners of a square. A charge $$q$$ is placed at each of the other two corners. If the net electrical force on $$Q$$ is zero, then $$Q/q$$ equals:
A
$$-1$$
B
$$1$$
C
$$ - {1 \over {\sqrt 2 }}$$
D
$$ - 2\sqrt 2 $$
2
AIEEE 2009
MCQ (Single Correct Answer)
+4
-1
Consider a rubber ball freely falling from a height $$h=4.9$$ $$m$$ onto a horizontal elastic plate. Assume that the duration of collision is negligible and the collision with the plate is totally elastic.

Then the velocity as a function of time and the height as a function of time will be :
A
AIEEE 2009 Physics - Motion in a Straight Line Question 99 English Option 1
B
AIEEE 2009 Physics - Motion in a Straight Line Question 99 English Option 2
C
AIEEE 2009 Physics - Motion in a Straight Line Question 99 English Option 3
D
AIEEE 2009 Physics - Motion in a Straight Line Question 99 English Option 4
3
AIEEE 2009
MCQ (Single Correct Answer)
+4
-1
(This question contains Statement-1 and Statement-2. Of the four choices given after the statements, choose the one that best describes the two statements.)

Statement-1 : For a charged particle moving from point $$P$$ to point $$Q$$, the net work done by an electrostatic field on the particle is independent of the path connecting point $$P$$ to point $$Q.$$
Statement-2 : The net work done by a conservative force on an object moving along a closed loop is zero.

A
Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.
B
Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement-1.
C
Statement- 1 is false, Statement- 2 is true.
D
Statement- 1 true, Statement- 2 is false
4
AIEEE 2009
MCQ (Single Correct Answer)
+4
-1
Two points $$P$$ and $$Q$$ are maintained at the potentials of $$10$$ $$V$$ and $$-4$$ $$V$$, respectively. The work done in moving $$100$$ electrons from $$P$$ to $$Q$$ is :
A
$$9.60 \times {10^{ - 17}}J$$
B
$$ - 2.24 \times {10^{ - 16}}J$$
C
$$ 2.24 \times {10^{ - 16}}J$$
D
$$- 9.60 \times {10^{ - 17}}J$$
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