1
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
The velocity of a particle is v = v0 + gt + ft2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is
A
v0 + g/2 + f
B
v0 + 2g + 3f
C
v0 + g/2 + f/3
D
v0 + g + f
2
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity 'v' that varies as $$v = \alpha \sqrt x $$. The displacement of the particle varies with time as
A
t2
B
t
C
t1/2
D
t3
3
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate $${f \over 2}$$ to come to rest. If the total distance traversed is 15 S, then
A
$$S = {1 \over 6}f{t^2}$$
B
$$S = ft$$
C
$$S = {1 \over 4}f{t^2}$$
D
$$S = {1 \over 72}f{t^2}$$
4
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
The relation between time t and distance x is t = ax2 + bx where a and b are constants. The acceleration is
A
2bv3
B
-2abv2
C
2av2
D
-2av3
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