1
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
The velocity of a particle is v = v0 + gt + ft2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is
A
v0 + g/2 + f
B
v0 + 2g + 3f
C
v0 + g/2 + f/3
D
v0 + g + f
2
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity 'v' that varies as $$v = \alpha \sqrt x $$. The displacement of the particle varies with time as
A
t2
B
t
C
t1/2
D
t3
3
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate $${f \over 2}$$ to come to rest. If the total distance traversed is 15 S, then
A
$$S = {1 \over 6}f{t^2}$$
B
$$S = ft$$
C
$$S = {1 \over 4}f{t^2}$$
D
$$S = {1 \over 72}f{t^2}$$
4
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
A particle is moving eastwards with a velocity of 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is
A
$${1 \over 2}m{s^{ - 2}}$$ towards north
B
$${1 \over {\sqrt 2 }}m{s^{ - 2}}$$ towards north-east
C
$${1 \over {\sqrt 2 }}m{s^{ - 2}}$$ towards north-west
D
zero
JEE Main Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
CBSE
Class 12