1
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to :
[g is the acceleration due to gravity]
A
t = 3.4$$\sqrt {\left( {{h \over g}} \right)} $$
B
t = 1.8$$\sqrt {\left( {{h \over g}} \right)} $$
C
t = $$\sqrt {{{2h} \over {3g}}} $$
D
t = $${2 \over 3}\sqrt {\left( {{h \over g}} \right)} $$
2
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height $${h \over 2}$$. The velocity versus height of the ball during its motion may be represented graphically by :
(graph are drawn schematically and on not to scale)
A
JEE Main 2020 (Online) 4th September Morning Slot Physics - Motion in a Straight Line Question 84 English Option 1
B
JEE Main 2020 (Online) 4th September Morning Slot Physics - Motion in a Straight Line Question 84 English Option 2
C
JEE Main 2020 (Online) 4th September Morning Slot Physics - Motion in a Straight Line Question 84 English Option 3
D
JEE Main 2020 (Online) 4th September Morning Slot Physics - Motion in a Straight Line Question 84 English Option 4
3
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Train A and train B are running on parallel tracks in the opposite directions with speeds of 36 km/hour and 72 km/hour, respectively. A person is walking in train A in the direction opposite to its motion with a speed of 1.8 km/ hour. Speed (in ms–1) of this person as observed from train B will be close to :
(take the distance between the tracks as negligible)
A
30.5 ms–1
B
29.5 ms–1
C
31.5 ms–1
D
28.5 ms–1
4
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is moving with speed v = b$$\sqrt x $$ along positive x-axis. Calculate the speed of the particle at time t = $$\tau $$(assume that the particle is at origin t = 0)
A
$${{{b^2}\tau } \over {\sqrt 2 }}$$
B
$${{b^2}\tau }$$
C
$${{{b^2}\tau } \over 2}$$
D
$${{{b^2}\tau } \over 4}$$
JEE Main Subjects
EXAM MAP