1
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
The relation between time t and distance x for a moving body is given as t = mx2 + nx, where m and n are constants. The retardation of the motion is : (When v stands for velocity)
A
2 mv3
B
2 mnv3
C
2nv3
D
2n2v3
2
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around :

(takes the value of g as 10 m/s2)
A
300 m
B
200 m
C
125 m
D
250 m
3
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
The instantaneous velocity of a particle moving in a straight line is given as $$V = \alpha t + \beta {t^2}$$, where $$\alpha$$ and $$\beta$$ are constants. The distance travelled by the particle between 1s and 2s is :
A
3$$\alpha$$ + 7$$\beta$$
B
$${3 \over 2}\alpha + {7 \over 3}\beta$$
C
$${\alpha \over 2} + {\beta \over 3}$$
D
$${3 \over 2}\alpha + {7 \over 2}\beta$$
4
JEE Main 2021 (Online) 25th July Morning Shift
+4
-1
Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap ? (Take g = 9.8 m/s2)
A
3 drops / 2 sconds
B
2 drops / second
C
1 drop / second
D
1 drop / 7 seconds
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