JEE Main 2018 (Offline) | Motion in a Straight Line Question 102 | Physics

The velocity-time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in $$15$$ $$s$$ and (ii) the time at which the car will catch up with the scooter are, respectively.

JEE Main 2018 (Online) 15th April Morning Slot Physics - Motion in a Straight Line Question 104 English

JEE Main 2018 (Online) 15th April Morning Slot Physics - Motion in a Straight Line Question 104 English

$$112.5$$ $$m$$ and $$22.5$$ $$s$$

$$337.5$$ $$m$$ and $$25$$ $$s$$

$$112.5$$ $$m$$ and $$15$$ $$s$$

$$225.5$$ $$m$$ and $$10$$ $$s$$

JEE Main 2018 (Online) 15th April Morning Slot

MCQ (Single Correct Answer)

-1

An automobile, travelling at $$40\,$$ km/h, can be stopped at a distance of $$40\,$$ m by applying brakes. If the same automobile is travelling at $$80\,$$ km/h, the minimum stopping distance, in metres, is (assume no skidding) :

$$45\,$$ m

$$100\,$$ m

$$150\,$$ m

$$160\,$$ m

JEE Main 2017 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

A car is standing 200 m behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration 2 m/s² and the car has acceleration 4 m/s² . The car will catch up with the bus after a time of :

$$\sqrt {110} \,s$$

$$\sqrt {120} \,s$$

$$10\,\,\sqrt 2 \,s$$

15 s

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