JEE Main 2021 (Online) 17th March Evening Shift | Motion Question 112 | Physics

A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to $${{81} \over {100}}$$ of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms^$$-$$2)

2.50 ms^$$-$$1

3.0 ms^$$-$$1

2.0 ms^$$-$$1

3.50 ms^$$-$$1

JEE Main 2021 (Online) 17th March Morning Shift

MCQ (Single Correct Answer)

-1

A car accelerates from rest at a constant rate $$\alpha$$ for some time after which it decelerates at a constant rate $$\beta$$ to come to rest. If the total time elapsed is t seconds, the total distance travelled is :

$${{4\alpha \beta } \over {(\alpha + \beta )}}{t^2}$$

$${{2\alpha \beta } \over {(\alpha + \beta )}}{t^2}$$

$${{\alpha \beta } \over {2(\alpha + \beta )}}{t^2}$$

$${{\alpha \beta } \over {4(\alpha + \beta )}}{t^2}$$

JEE Main 2021 (Online) 16th March Evening Shift

MCQ (Single Correct Answer)

-1

A mosquito is moving with a velocity $$\overrightarrow v = 0.5{t^2}\widehat i + 3t\widehat j + 9\widehat k$$ m/s and accelerating in uniform conditions. What will be the direction of mosquito after 2 s?

$${\tan ^{ - 1}}\left( {{\sqrt {85} } \over 6}\right)$$ from y-axis

$${\tan ^{ - 1}}\left( {{5 \over 2}} \right)$$ from y-axis

$${\tan ^{ - 1}}\left( {{2 \over 3}} \right)$$ from x-axis

$${\tan ^{ - 1}}\left( {{5 \over 2}} \right)$$ from x-axis

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