JEE Main 2014 (Offline) | Motion Question 162 | Physics

From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is:

2gH = n²u²

gH = (n - 2)²u²

2gH = nu²(n - 2)

gH = (n - 2)u²

JEE Main 2013 (Offline)

MCQ (Single Correct Answer)

-1

A projectile is given an initial velocity of $$\left( {\widehat i + 2\widehat j} \right)$$ m/s, where $${\widehat i}$$ is along the ground and $${\widehat j}$$ is along the vertical. If g = 10 m/s², the equation of its trajectory is:

y = x - 5x²

y = 2x - 5x²

4y = 2x - 5x²

4y = 2x - 25x²

AIEEE 2012

MCQ (Single Correct Answer)

-1

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be

$$20\sqrt 2 $$ m

10 m

$$10\sqrt 2 $$ m

20 m

AIEEE 2011

MCQ (Single Correct Answer)

-1

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is :

$$\pi {{{v^4}} \over {{g^2}}}$$

$${\pi \over 2}{{{v^4}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over g}$$

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