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1
JEE Main 2021 (Online) 18th March Evening Shift
+4
-1
The velocity $$-$$ displacement graph of a particle is shown in the figure.

The acceleration $$-$$ displacement graph of the same particle is represented by :
A
B
C
D
2
JEE Main 2021 (Online) 18th March Morning Shift
+4
-1
The position, velocity and acceleration of a particle moving with a constant acceleration can be represented by :
A
B
C
D
3
JEE Main 2021 (Online) 17th March Evening Shift
+4
-1
The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0; then its displacement after time (t = 1) is :
A
v0 + g + f
B
v0 + $${g \over 2}$$ + $${F \over 3}$$
C
v0 + 2g + 3F
D
v0 + $${g \over 2}$$ + F
4
JEE Main 2021 (Online) 17th March Evening Shift
A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to $${{81} \over {100}}$$ of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms$$-$$2)
2.50 ms$$-$$1
3.0 ms$$-$$1
2.0 ms$$-$$1
3.50 ms$$-$$1