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1
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
The velocity $$-$$ displacement graph of a particle is shown in the figure.

JEE Main 2021 (Online) 18th March Evening Shift Physics - Motion Question 53 English
The acceleration $$-$$ displacement graph of the same particle is represented by :
A
JEE Main 2021 (Online) 18th March Evening Shift Physics - Motion Question 53 English Option 1
B
JEE Main 2021 (Online) 18th March Evening Shift Physics - Motion Question 53 English Option 2
C
JEE Main 2021 (Online) 18th March Evening Shift Physics - Motion Question 53 English Option 3
D
JEE Main 2021 (Online) 18th March Evening Shift Physics - Motion Question 53 English Option 4
2
JEE Main 2021 (Online) 18th March Morning Shift
MCQ (Single Correct Answer)
+4
-1
The position, velocity and acceleration of a particle moving with a constant acceleration can be represented by :
A
JEE Main 2021 (Online) 18th March Morning Shift Physics - Motion Question 55 English Option 1
B
JEE Main 2021 (Online) 18th March Morning Shift Physics - Motion Question 55 English Option 2
C
JEE Main 2021 (Online) 18th March Morning Shift Physics - Motion Question 55 English Option 3
D
JEE Main 2021 (Online) 18th March Morning Shift Physics - Motion Question 55 English Option 4
3
JEE Main 2021 (Online) 17th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0; then its displacement after time (t = 1) is :
A
v0 + g + f
B
v0 + $${g \over 2}$$ + $${F \over 3}$$
C
v0 + 2g + 3F
D
v0 + $${g \over 2}$$ + F
4
JEE Main 2021 (Online) 17th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to $${{81} \over {100}}$$ of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms$$-$$2)
A
2.50 ms$$-$$1
B
3.0 ms$$-$$1
C
2.0 ms$$-$$1
D
3.50 ms$$-$$1
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