JEE Main 2022 (Online) 29th July Evening Shift | Motion in a Straight Line Question 36 | Physics

A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

g/2n

g/n

2gn

g/2n²

JEE Main 2022 (Online) 29th July Evening Shift

MCQ (Single Correct Answer)

-1

A ball is released from a height h. If $$t_{1}$$ and $$t_{2}$$ be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between $$t_{1}$$ and $$t_{2}$$.

$$t_{1}=(\sqrt{2}) t_{2}$$

$$t_{1}=(\sqrt{2}-1) t_{2}$$

$$t_{2}=(\sqrt{2}+1) t_{1}$$

$$t_{2}=(\sqrt{2}-1) t_{1}$$

JEE Main 2022 (Online) 29th July Morning Shift

MCQ (Single Correct Answer)

-1

A ball is thrown up vertically with a certain velocity so that, it reaches a maximum height h. Find the ratio of the times in which it is at height $$\frac{h}{3}$$ while going up and coming down respectively.

$$\frac{\sqrt{2}-1}{\sqrt{2}+1}$$

$$\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$$

$$\frac{\sqrt{3}-1}{\sqrt{3}+1}$$

$$\frac{1}{3}$$

JEE Main 2022 (Online) 29th July Morning Shift

MCQ (Single Correct Answer)

-1

If $$\mathrm{t}=\sqrt{x}+4$$, then $$\left(\frac{\mathrm{d} x}{\mathrm{~d} t}\right)_{\mathrm{t}=4}$$ is :

zero

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