1
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements

Statement I : Area under velocity- time graph gives the distance travelled by the body in a given time.

Statement II : Area under acceleration- time graph is equal to the change in velocity- in the given time.

In the light of given statements, choose the correct answer from the options given below.

A
Both Statement I and Statement II are False.
B
Both Statement I and Statement II are true.
C
Statement I is incorrect but Statement II is true.
D
Statement I is correct but Statement II is false.
2
JEE Main 2023 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A particle starts with an initial velocity of $$10.0 \mathrm{~ms}^{-1}$$ along $$x$$-direction and accelerates uniformly at the rate of $$2.0 \mathrm{~ms}^{-2}$$. The time taken by the particle to reach the velocity of $$60.0 \mathrm{~ms}^{-1}$$ is __________.

A
30s
B
6s
C
3s
D
25s
3
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An object moves with speed $$v_1,v_2$$ and $$v_3$$ along a line segment AB, BC and CD respectively as shown in figure. Where AB = BC and AD = 3AB, then average speed of the object will be:

JEE Main 2023 (Online) 1st February Morning Shift Physics - Motion in a Straight Line Question 41 English

A
$${{{v_1}{v_2}{v_3}} \over {3({v_1}{v_2} + {v_2}{v_3} + {v_3}{v_1})}}$$
B
$${{({v_1} + {v_2} + {v_3})} \over 3}$$
C
$${{({v_1} + {v_2} + {v_3})} \over {3{v_1}{v_2}{v_3}}}$$
D
$${{3{v_1}{v_2}{v_3}} \over {({v_1}{v_2} + {v_2}{v_3} + {v_3}{v_1})}}$$
4
JEE Main 2023 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A vehicle travels $4 \mathrm{~km}$ with speed of $3 \mathrm{~km} / \mathrm{h}$ and another $4 \mathrm{~km}$ with speed of $5 \mathrm{~km} / \mathrm{h}$, then its average speed is
A
$3.75 \mathrm{~km} / \mathrm{h}$
B
$4.25 \mathrm{~km} / \mathrm{h}$
C
$3.50 \mathrm{~km} / \mathrm{h}$
D
$4.00 \mathrm{~km} / \mathrm{h}$
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