1
JEE Main 2021 (Online) 25th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
An engine of a train, moving with uniform acceleration, passes the signal-post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is :
A
$${{u + v} \over 2}$$
B
$$\sqrt {{{{v^2} - {u^2}} \over 2}} $$
C
$${{v - u} \over 2}$$
D
$$\sqrt {{{{v^2} + {u^2}} \over 2}} $$
2
JEE Main 2021 (Online) 24th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph?

JEE Main 2021 (Online) 24th February Morning Shift Physics - Motion in a Straight Line Question 79 English
A
JEE Main 2021 (Online) 24th February Morning Shift Physics - Motion in a Straight Line Question 79 English Option 1
B
JEE Main 2021 (Online) 24th February Morning Shift Physics - Motion in a Straight Line Question 79 English Option 2
C
JEE Main 2021 (Online) 24th February Morning Shift Physics - Motion in a Straight Line Question 79 English Option 3
D
JEE Main 2021 (Online) 24th February Morning Shift Physics - Motion in a Straight Line Question 79 English Option 4
3
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is : JEE Main 2020 (Online) 5th September Evening Slot Physics - Motion in a Straight Line Question 80 English
A
12 m
B
11 m
C
$${{49} \over 4}$$ m
D
$${{37} \over 3}$$ m
4
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to :
[g is the acceleration due to gravity]
A
t = 3.4$$\sqrt {\left( {{h \over g}} \right)} $$
B
t = 1.8$$\sqrt {\left( {{h \over g}} \right)} $$
C
t = $$\sqrt {{{2h} \over {3g}}} $$
D
t = $${2 \over 3}\sqrt {\left( {{h \over g}} \right)} $$
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