1
JEE Main 2021 (Online) 18th March Morning Shift
+4
-1
The position, velocity and acceleration of a particle moving with a constant acceleration can be represented by :
A
B
C
D
2
JEE Main 2021 (Online) 17th March Evening Shift
+4
-1
The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0; then its displacement after time (t = 1) is :
A
v0 + g + f
B
v0 + $${g \over 2}$$ + $${F \over 3}$$
C
v0 + 2g + 3F
D
v0 + $${g \over 2}$$ + F
3
JEE Main 2021 (Online) 17th March Evening Shift
+4
-1
A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to $${{81} \over {100}}$$ of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms$$-$$2)
A
2.50 ms$$-$$1
B
3.0 ms$$-$$1
C
2.0 ms$$-$$1
D
3.50 ms$$-$$1
4
JEE Main 2021 (Online) 17th March Morning Shift
+4
-1
A car accelerates from rest at a constant rate $$\alpha$$ for some time after which it decelerates at a constant rate $$\beta$$ to come to rest. If the total time elapsed is t seconds, the total distance travelled is :
A
$${{4\alpha \beta } \over {(\alpha + \beta )}}{t^2}$$
B
$${{2\alpha \beta } \over {(\alpha + \beta )}}{t^2}$$
C
$${{\alpha \beta } \over {2(\alpha + \beta )}}{t^2}$$
D
$${{\alpha \beta } \over {4(\alpha + \beta )}}{t^2}$$
EXAM MAP
Medical
NEET
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
CBSE
Class 12