1
JEE Main 2019 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed '$$\upsilon $$' more than that of car B. Both the cars start from rest and travel with constant acceleration a1 and a2 respectively. Then '$$\upsilon $$' is equal to :
A
$${{2{a_1}{a_2}} \over {{a_1} + {a_2}}}t$$
B
$$\sqrt {2{a_1}{a_2}} t$$
C
$$\sqrt {{a_1}{a_2}} t$$
D
$${{{a_1} + {a_2}} \over 2}t$$
2
JEE Main 2019 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The position co-ordinates of a particle moving in a 3-D coordinate system is given by
x = a cos$$\omega $$t
y = a sin$$\omega $$t and
z = a$$\omega $$t

The speed of the particle is :
A
$$\sqrt 2 \,a\omega $$
B
$$a\omega $$
C
$$\sqrt 3 \,a\omega $$
D
2a$$\omega $$
3
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is moving with a velocity

$$\overrightarrow v \, = K(y\widehat i + x\widehat j),$$ where K is a constant.

The general equation for its path is :
A
y = x2 + constant
B
y2 = x + constant
C
y2 = x2 + constant
D
xy = constant
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.
A
JEE Main 2018 (Offline) Physics - Motion Question 151 English Option 1
B
JEE Main 2018 (Offline) Physics - Motion Question 151 English Option 2
C
JEE Main 2018 (Offline) Physics - Motion Question 151 English Option 3
D
JEE Main 2018 (Offline) Physics - Motion Question 151 English Option 4
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