AIEEE 2006 | Motion Question 172 | Physics

A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity 'v' that varies as $$v = \alpha \sqrt x $$. The displacement of the particle varies with time as

t²

t^1/2

t³

AIEEE 2005

MCQ (Single Correct Answer)

-1

A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate $${f \over 2}$$ to come to rest. If the total distance traversed is 15 S, then

$$S = {1 \over 6}f{t^2}$$

$$S = ft$$

$$S = {1 \over 4}f{t^2}$$

$$S = {1 \over 72}f{t^2}$$

AIEEE 2005

MCQ (Single Correct Answer)

-1

The relation between time t and distance x is t = ax² + bx where a and b are constants. The acceleration is

2bv³

-2abv²

2av²

-2av³

AIEEE 2005

MCQ (Single Correct Answer)

-1

A particle is moving eastwards with a velocity of 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is

$${1 \over 2}m{s^{ - 2}}$$ towards north

$${1 \over {\sqrt 2 }}m{s^{ - 2}}$$ towards north-east

$${1 \over {\sqrt 2 }}m{s^{ - 2}}$$ towards north-west

zero

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