JEE Main 2024 (Online) 4th April Morning Shift | Current Electricity Question 69 | Physics

To measure the internal resistance of a battery, potentiometer is used. For $$R=10 \Omega$$, the balance point is observed at $$l=500 \mathrm{~cm}$$ and for $$\mathrm{R}=1 \Omega$$ the balance point is observed at $$l=400 \mathrm{~cm}$$. The internal resistance of the battery is approximately :

$$0.1 \Omega$$

$$0.3 \Omega$$

$$0.2 \Omega$$

$$0.4 \Omega$$

JEE Main 2024 (Online) 1st February Evening Shift

MCQ (Single Correct Answer)

-1

In a metre-bridge when a resistance in the left gap is $2 \Omega$ and unknown resistance in the right gap, the balance length is found to be $40 \mathrm{~cm}$. On shunting the unknown resistance with $2 \Omega$, the balance length changes by :

$62.5 $

$22.5 \mathrm{~cm}$

$20 \mathrm{~cm}$

$65 \mathrm{~cm}$

JEE Main 2024 (Online) 1st February Evening Shift

MCQ (Single Correct Answer)

-1

In an ammeter, $5 \%$ of the main current passes through the galvanometer. If resistance of the galvanometer is $\mathrm{G}$, the resistance of ammeter will be :

$199 \mathrm{~G}$

$200 \mathrm{~G}$

$\frac{G}{20}$

$\frac{\mathrm{G}}{199}$

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

The reading in the ideal voltmeter $(\mathrm{V})$ shown in the given circuit diagram is :

JEE Main 2024 (Online) 1st February Morning Shift Physics - Current Electricity Question 93 English