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JEE Mains Previous Years Questions with Solutions

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AIEEE 2005

MCQ (Single Correct Answer)
In a potentiometer experiment the balancing with a cell is at length $$240$$ $$cm.$$ On shunting the cell with a resistance of $$2\Omega ,$$ the balancing length becomes $$120$$ $$cm$$. The internal resistance of the cell is
A
$$0.5\Omega $$
B
$$1\Omega $$
C
$$2\Omega $$
D
$$4\Omega $$

Explanation

The internal resistance of the cell,

$$r = \left( {{{{\ell _1} - {\ell _2}} \over {{\ell _2}}}} \right) \times R$$

$$ = {{240 - 120} \over {120}} \times 2 = 2\Omega $$

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