JEE Main 2023 (Online) 31st January Morning Shift | Current Electricity Question 80 | Physics

The drift velocity of electrons for a conductor connected in an electrical circuit is $$\mathrm{V}_{\mathrm{d}}$$. The conductor in now replaced by another conductor with same material and same length but double the area of cross section. The applied voltage remains same. The new drift velocity of electrons will be

$$\frac{V_{d}}{4}$$

$$\mathrm{V}_{\mathrm{d}}$$

$$2 \mathrm{~V}_{\mathrm{d}}$$

$$\frac{V_{d}}{2}$$

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

The equivalent resistance between $A$ and $B$ is _________.

JEE Main 2023 (Online) 30th January Evening Shift Physics - Current Electricity Question 89 English

$\frac{1}{2} \Omega$

$\frac{2}{3} \Omega$

$\frac{3}{2} \Omega$

$\frac{1}{3} \Omega$

JEE Main 2023 (Online) 30th January Morning Shift

MCQ (Single Correct Answer)

-1

The charge flowing in a conductor changes with time as $$\mathrm{Q}(\mathrm{t})=\alpha \mathrm{t}-\beta \mathrm{t}^{2}+\gamma \mathrm{t}^{3}$$. Where $$\alpha, \beta$$ and $$\gamma$$ are constants. Minimum value of current is :

$$\beta-\frac{\alpha^{2}}{3 \gamma}$$

$$\alpha-\frac{3 \beta^{2}}{\gamma}$$

$$\alpha-\frac{\beta^{2}}{3 \gamma}$$

$$\alpha-\frac{\gamma^{2}}{3 \beta}$$

JEE Main 2023 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

With the help of potentiometer, we can determine the value of emf of a given cell. The sensitivity of the potentiometer is

(A) directly proportional to the length of the potentiometer wire

(B) directly proportional to the potential gradient of the wire

(D) inversely proportional to the length of the potentiometer wire