A conducting wire of length 'l', area of cross-section A and electric resistivity $$\rho$$ is connected between the terminals of a battery. A potential difference V is developed between its ends, causing an electric current.

If the length of the wire of the same material is doubled and the area of cross-section is halved, the resultant current would be :

A wire of 1$$\Omega$$ has a length of 1 m. It is stretched till its length increases by 25%. The percentage change in resistance to the nearest integer is :

Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is :

A current through a wire depends on time as

i = $$\alpha$$₀t + $$\beta$$t²

where $$\alpha$$₀ = 20 A/s and $$\beta$$ = 8 As^$$-$$2. Find the charge crossed through a section of the wire in 15 s.