JEE Main 2022 (Online) 25th June Evening Shift | Current Electricity Question 69 | Physics

JEE Main 2022 (Online) 25th June Evening Shift

MCQ (Single Correct Answer)

-1

Two cells of same emf but different internal resistances r₁ and r₂ are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, is :

r₂ $$-$$ r₁

r₁ $$-$$ r₂

r₁

r₂

JEE Main 2022 (Online) 25th June Evening Shift

MCQ (Single Correct Answer)

-1

If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be:

$${{KS} \over {(S + G)}}$$

$${{(G + S)} \over {nKS}}$$

$${{nKS} \over {(G + S)}}$$

$${{nK(G + S)} \over S}$$

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

In the figure, a very large plane sheet of positive charge is shown. P₁ and P₂ are two points at distance l and 2l from the charge distribution. If $$\sigma$$ is the surface charge density, then the magnitude of electric fields E₁ and E₂ at P₁ and P₂ respectively are :

JEE Main 2022 (Online) 25th June Morning Shift Physics - Current Electricity Question 58 English

$${E_1} = \sigma /{\varepsilon _0},\,{E_2} = \sigma /2{\varepsilon _0}$$

$${E_1} = 2\sigma /{\varepsilon _0},\,{E_2} = \sigma /{\varepsilon _0}$$

$${E_1} = {E_2} = \sigma /2{\varepsilon _0}$$

$${E_1} = {E_2} = \sigma /{\varepsilon _0}$$

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

A teacher in his physics laboratory allotted an experiment to determine the resistance (G) of a galvanometer. Students took the observations for $${1 \over 3}$$ deflection in the galvanometer. Which of the below is true for measuring value of G?

$${1 \over 3}$$ deflection method cannot be used for determining the resistance of the galvanometer.

$${1 \over 3}$$ deflection method can be used and in this case the G equals to twice the value of shunt resistances.

$${1 \over 3}$$ deflection method can be used and in this case, the G equals to three times the value of shunt resistances.

$${1 \over 3}$$ deflection method can be used and in this case the G value equals to the shunt resistances.

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