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1
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The reading in the ideal voltmeter $(\mathrm{V})$ shown in the given circuit diagram is :

JEE Main 2024 (Online) 1st February Morning Shift Physics - Current Electricity Question 93 English
A
$3 \mathrm{~V}$
B
$10 \mathrm{~V}$
C
$5 \mathrm{~V}$
D
$0 \mathrm{~V}$
2
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A galvanometer has a resistance of $50 ~\Omega$ and it allows maximum current of $5 \mathrm{~mA}$. It can be converted into voltmeter to measure upto $100 \mathrm{~V}$ by connecting in series a resistor of resistance :
A
$19500 \Omega$
B
$5975 \Omega$
C
$20050 \Omega$
D
$19950 \Omega$
3
JEE Main 2024 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

By what percentage will the illumination of the lamp decrease if the current drops by 20%?

A
26%
B
36%
C
46%
D
56%
4
JEE Main 2024 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The resistance per centimeter of a meter bridge wire is $$r$$, with $$X \Omega$$ resistance in left gap. Balancing length from left end is at $$40 \mathrm{~cm}$$ with $$25 \Omega$$ resistance in right gap. Now the wire is replaced by another wire of $$2 r$$ resistance per centimeter. The new balancing length for same settings will be at

A
10 cm
B
80 cm
C
40 cm
D
20 cm

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