1
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A moving coil galvanometer, having a resistance G, produces full scale deflection when a current Ig flows through it. This galvanometer can be converted into (i) an ammeter of range 0 to I0(I0 > Ig) by connecting a shunt resistance RA to it and (ii) into a voltmeter of range 0 to V (V = GI0) by connecting a series resistance RV to it. Then,
A
$${R_A}{R_V} = {G^2}$$ and $${{{R_A}} \over {{R_V}}} = {{{I_g}} \over {\left( {{I_0} - {I_g}} \right)}}$$
B
$${R_A}{R_V} = {G^2}\left( {{{{I_g}} \over {{I_0} - {I_g}}}} \right)$$ and $${{{R_A}} \over {{R_V}}} = {\left( {{{{I_0} - {I_g}} \over {{I_g}}}} \right)^2}$$
C
$${R_A}{R_V} = {G^2}\left( {{{{I_0} - {I_g}} \over {{I_g}}}} \right)$$ and $${{{R_A}} \over {{R_V}}} = {\left( {{{{I_g}} \over {{I_0} - {I_g}}}} \right)^2}$$
D
$${R_A}{R_V} = {G^2}$$ and $${{{R_A}} \over {{R_V}}} = {\left( {{{{I_g}} \over {{I_0} - {I_g}}}} \right)^2}$$
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the network is 4 Watt. The value of R is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 210 English
A
16 $$\Omega $$
B
1 $$\Omega $$
C
8 $$\Omega $$
D
6 $$\Omega $$
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A galvanometer of resistance 100 $$\Omega $$ has 50 divisions on its scale and has sensitivitv of 20 $$\mu $$A/division. It is to be converted to a voltmeter with three ranges of 0-2V, 0-10 V and 0-20 V. The appropriate circuit to do so is
A
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 209 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 209 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 209 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 209 English Option 4
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained : JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 208 English
If V0 is almost zero, identify the correct statement :
A
The value of the resistance R is 1.5 $$\Omega $$
B
The emf of the battery is l.5 V and its internal resistance is 1.5 $$\Omega $$
C
The emf of the battery is l.5 V and the value of R is 1.5 $$\Omega $$
D
The potential difference across the battery is 1.5 V when it sends a current of 1000 mA
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