JEE Main 2024 (Online) 1st February Morning Shift | Current Electricity Question 27 | Physics

A galvanometer has a resistance of $50 ~\Omega$ and it allows maximum current of $5 \mathrm{~mA}$. It can be converted into voltmeter to measure upto $100 \mathrm{~V}$ by connecting in series a resistor of resistance :

$19500 \Omega$

$5975 \Omega$

$20050 \Omega$

$19950 \Omega$

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

By what percentage will the illumination of the lamp decrease if the current drops by 20%?

26%

36%

46%

56%

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

The resistance per centimeter of a meter bridge wire is $$r$$, with $$X \Omega$$ resistance in left gap. Balancing length from left end is at $$40 \mathrm{~cm}$$ with $$25 \Omega$$ resistance in right gap. Now the wire is replaced by another wire of $$2 r$$ resistance per centimeter. The new balancing length for same settings will be at

10 cm

80 cm

40 cm

20 cm

JEE Main 2024 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

Two conductors have the same resistances at $$0^{\circ} \mathrm{C}$$ but their temperature coefficients of resistance are $$\alpha_1$$ and $$\alpha_2$$. The respective temperature coefficients for their series and parallel combinations are :

$$\alpha_1+\alpha_2, \frac{\alpha_1 \alpha_2}{\alpha_1+\alpha_2}$$

$$\frac{\alpha_1+\alpha_2}{2}, \frac{\alpha_1+\alpha_2}{2}$$

$$\alpha_1+\alpha_2, \frac{\alpha_1+\alpha_2}{2}$$

$$\frac{\alpha_1+\alpha_2}{2}, \alpha_1+\alpha_2$$

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