1
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two electric bulbs, rated at (25 W, 220 V) and (100 W, 220 V), are connected in series across a 220 V voltage source. If the 25 W and 100 W bulbs draw powers P1 and P2 respectively, then :
A
P1 = 4W, P2 = 16 W
B
P1 = 16W, P2 = 4 W
C
P1 = 9W, P2 = 16 W
D
P1 = 16W, P2 = 9 W
2
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The galvanometer deflection, when key K1 is closed but K2 is open, equals $$\theta $$0 (see figure). On closing K2 also and adjusting R2 to 5$$\Omega $$, the deflection in galvanometer becomes $${{{\theta _0}} \over 5}.$$ . The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery] :

JEE Main 2019 (Online) 12th January Morning Slot Physics - Current Electricity Question 265 English
A
5 $$\Omega $$
B
25 $$\Omega $$
C
12 $$\Omega $$
D
22 $$\Omega $$
3
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
An ideal battery of 4 V and resistance R are connected in series in the primary circuit of a potentiometer of length 1 m and esistance 5 $$\Omega $$. The value of R, to give a potential difference of 5 mV across 10 cm of potentiometer wire, is :
A
480 $$\Omega $$
B
495 $$\Omega $$
C
490 $$\Omega $$
D
395 $$\Omega $$
4
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A galvanometer having a resistance of 20 $$\Omega $$ and 30 divisions on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt, is:
A
120 $$\Omega $$
B
125 $$\Omega $$
C
80 $$\Omega $$
D
100 $$\Omega $$
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