AIEEE 2003 | Current Electricity Question 327 | Physics

An ammeter reads upto $$1$$ ampere. Its internal resistance is $$0.81$$ $$ohm$$. To increase the range to $$10$$ $$A$$ the value of the required shunt is

$$0.03\,\Omega $$

$$0.3\,\Omega $$

$$0.9\,\Omega $$

$$0.09\,\Omega $$

AIEEE 2002

MCQ (Single Correct Answer)

-1

If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a

low resistance in parallel

high resistance in parallel

high resistance in series

low resistance in series

AIEEE 2002

MCQ (Single Correct Answer)

-1

A wire when connected to $$220$$ $$V$$ mains supply has power dissipation $${P_1}.$$ Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is $${P_2}.$$ Then $${P_2}:{P_1}$$ is

$$1$$

$$4$$

$$2$$

$$3$$

AIEEE 2002

MCQ (Single Correct Answer)

-1

If $${\theta _1},$$ is the inversion temperature, $${\theta _n}$$ is the neutral temperature, $${\theta _c}$$ is the temperature of the cold junction, then

$${\theta _i} + {\theta _c} = {\theta _n}$$

$${\theta _i} - {\theta _c} = 2{\theta _n}$$

$${{{\theta _i} + {\theta _C}} \over 2} = {\theta _n}$$

$${\theta _c} - {\theta _i} = 2{\theta _n}$$

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