1
JEE Main 2015 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
For a simple pendulum, a graph is plotted between its kinetic energy $$(KE)$$ and potential energy $$(PE)$$ against its displacement $$d.$$ Which one of the following represents these correctly?
$$(graphs$$ $$are$$ $$schematic$$ $$and$$ $$not$$ $$drawn$$ $$to$$ $$scale)$$
A
JEE Main 2015 (Offline) Physics - Simple Harmonic Motion Question 124 English Option 1
B
JEE Main 2015 (Offline) Physics - Simple Harmonic Motion Question 124 English Option 2
C
JEE Main 2015 (Offline) Physics - Simple Harmonic Motion Question 124 English Option 3
D
JEE Main 2015 (Offline) Physics - Simple Harmonic Motion Question 124 English Option 4
2
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
A particle moves with simple harmonic motion in a straight line. In first $$\tau s,$$ after starting from rest it travels a distance $$a,$$ and in next $$\tau s$$ it travels $$2a,$$ in same direction, then:
A
amplitude of motion is $$3a$$
B
time period of oscillations is $$8\tau $$
C
amplitude of motion is $$4a$$
D
time period of oscillations is $$6\tau $$
3
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass $$M.$$ The piston and the cylinder have equal cross sectional area $$A$$. When the piston is in equilibrium, the volume of the gas is $${V_0}$$ and its pressure is $${P_0}.$$ The piston is slightly displaced from the equilibrium position and released,. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frquency
A
$${1 \over {2\pi }}\,{{A\gamma {P_0}} \over {{V_0}M}}$$
B
$${1 \over {2\pi }}\,{{{V_0}M{P_0}} \over {{A^2}\gamma }}$$
C
$${1 \over {2\pi }}\,\sqrt {{{A\gamma {P_0}} \over {{V_0}M}}} $$
D
$${1 \over {2\pi }}\,\sqrt {{{M{V_0}} \over {A\gamma {P_0}}}} $$
4
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The amplitude of a damped oscillator decreases to $$0.9$$ times its original magnitude in $$5s$$. In another $$10s$$ it will decrease to $$\alpha $$ times its original magnitude, where $$\alpha $$ equals
A
$$0.7$$
B
$$0.81$$
C
$$0.729$$
D
$$0.6$$
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