AIEEE 2007 | Simple Harmonic Motion Question 146 | Physics

A point mass oscillates along the $$x$$-axis according to the law $$x = {x_0}\,\cos \left( {\omega t - \pi /4} \right).$$ If the acceleration of the particle is written as $$a = A\,\cos \left( {\omega t + \delta } \right),$$ then

$$A = {x_0}{\omega ^2},\,\,\delta = 3\pi /4$$

$$A = {x_0},\,\,\delta = - \pi /4$$

$$A = {x_0}{\omega ^2},\,\,\delta = \pi /4$$

$$A = {x_0}{\omega ^2},\,\,\delta = - \pi /4$$

AIEEE 2007

MCQ (Single Correct Answer)

-1

The displacement of an object attached to a spring and executing simple harmonic motion is given by $$x = 2 \times {10^{ - 2}}$$ $$cos$$ $$\pi t$$ metre. The time at which the maximum speed first occurs is

$$0.25$$ $$s$$

$$0.5$$ $$s$$

$$0.75$$ $$s$$

$$0.125$$ $$s$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

The maximum velocity of a particle, executing simple harmonic motion with an amplitude $$7$$ $$mm,$$ is $$4.4$$ $$m/s.$$ The period of oscillation is

$$0.01$$ $$s$$

$$10$$ $$s$$

$$0.1$$ $$s$$

$$100$$ $$s$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

A coin is placed on a horizontal platform which undergoes vertical simple harmonic motoin of angular frequency $$\omega .$$ The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time

at the mean position of the platform

for an amplitude of $${g \over {{\omega ^2}}}$$

For an amplitude of $${{{g^2}} \over {{\omega ^2}}}$$

at the height position of the platform

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