AIEEE 2006 | Simple Harmonic Motion Question 149 | Physics

A coin is placed on a horizontal platform which undergoes vertical simple harmonic motoin of angular frequency $$\omega .$$ The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time

at the mean position of the platform

for an amplitude of $${g \over {{\omega ^2}}}$$

For an amplitude of $${{{g^2}} \over {{\omega ^2}}}$$

at the height position of the platform

AIEEE 2006

MCQ (Single Correct Answer)

-1

Starting from the origin a body oscillates simple harmonically with a period of $$2$$ $$s.$$ After what time will its kinetic energy be $$75\% $$ of the total energy?

$${1 \over 6}s$$

$${1 \over 4}s$$

$${1 \over 3}s$$

$${1 \over 12}s$$

AIEEE 2005

MCQ (Single Correct Answer)

-1

If a simple harmonic motion is represented by $${{{d^2}x} \over {d{t^2}}} + \alpha x = 0.$$ its time period is

$${{2\pi } \over {\sqrt \alpha }}$$

$${{2\pi } \over \alpha }$$

$$2\pi \sqrt \alpha $$

$$2\pi \alpha $$

AIEEE 2005

MCQ (Single Correct Answer)

-1

The bob of a simple pendulum is a spherical hollow ball filled with water. A plugged hole near the bottom of the oscillating bob gets suddenly unplugged. During observation, till water is coming out, the time period of oscillation would

first decrease and then increase to the original value

first increase and then decrease to the original value

increase towards a saturation value

remain unchanged

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