Consider the following organic reaction sequence. Choose the final product $(X)$ from the following (consider the major product in all intermediate reactions)

The number of compounds from the following which can undergo reaction with $\mathrm{Br}_2 / \mathrm{KOH}$ (alcoholic) to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is :

Consider the following reactions. Total number of electrons in the $\pi$ bonds and lone pair of electrons in the product $(X)$ is :

Treatment of a gas ' $X$ ' with a freshly prepared ferrous sulphate solution gives a compound ' $Y$ ' as a brown ring. The compounds X and Y are.