1
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The eccentricity of an ellipse $E$ with centre at the origin $O$ is $\frac{\sqrt{3}}{2}$ and its directrices are $x= \pm \frac{4 \sqrt{6}}{3}$. Let $\mathrm{H}: \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1$ be a hyperbola whose eccentricity is equal to the length of semi-major axis of E , and whose length of latus rectum is equal to the length of minor axis of E . Then the distance between the foci of H is :

A

$\frac{4 \sqrt{2}}{\sqrt{7}}$

B

$\frac{4 \sqrt{2}}{7}$

C

$\frac{4}{\sqrt{7}}$

D

$\frac{8}{7}$

2
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $x=9$ be a directrix of an ellipse E , whose centre is at the origin and eccentricity is $\frac{1}{3}$. Let $\mathrm{P}(\alpha, 0)$, $\alpha>0$, be a focus of E and AB be a chord passing through P . Then the locus of the mid point of AB is :

A

$$ 9 y^2=8 x(1-x) $$

B

$$ 3 y^2=4 x(1-x) $$

C

$$ 9 y^2=8 x(x-1) $$

D

$$ 3 y^2=4 x(x-1) $$

3
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If $\sin \left(\tan ^{-1}(x \sqrt{2})\right)=\cot \left(\sin ^{-1} \sqrt{1-x^2}\right), x \in(0,1)$, then the value of $x$ is:

A

$\frac{1}{2}$

B

${\frac{1}{3}}$

C
$\frac{2}{3}$
D
$\frac{5}{8}$

4
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The shortest distance between the lines $\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}$ and $\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}$ is:

A

$$ \frac{5 \sqrt{6}}{6} $$

B

$$ 2 \sqrt{5} $$

C

$$ 3 \sqrt{5} $$

D

$$ 4 \sqrt{5} $$

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