1
JEE Main 2025 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1

The truth table for the circuit given below is:

JEE Main 2025 (Online) 29th January Evening Shift Physics - Semiconductor Question 2 English
A
ABY
000
111
101
011
B
ABY
000
101
010
110
C
ABY
000
100
110
011
D
ABY
000
011
101
110
2
JEE Main 2025 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
JEE Main 2025 (Online) 29th January Evening Shift Physics - Heat and Thermodynamics Question 6 English

A poly-atomic molecule $\left(C_V=3 R, C_P=4 R\right.$, where $R$ is gas constant) goes from phase space point $\mathrm{A}\left(\mathrm{P}_{\mathrm{A}}=10^5 \mathrm{~Pa}, \mathrm{~V}_{\mathrm{A}}=4 \times 10^{-6} \mathrm{~m}^3\right)$ to point $\mathrm{B}\left(\mathrm{P}_{\mathrm{B}}=5 \times 10^4 \mathrm{~Pa}, \mathrm{~V}_{\mathrm{B}}=6 \times 10^{-6} \mathrm{~m}^3\right)$ to point $\mathrm{C}\left(\mathrm{P}_{\mathrm{C}}=10^4\right.$ $\mathrm{Pa}, \mathrm{V}_C=8 \times 10^{-6} \mathrm{~m}^3$ ). A to $B$ is an adiabatic path and $B$ to $C$ is an isothermal path.

The net heat absorbed per unit mole by the system is :

A
$500 \mathrm{R}(\ln 3+\ln 4)$
B
$450 \mathrm{R}(\ln 4-\ln 3)$
C
$500 \mathrm{R} \ln 2$
D
$400 \mathrm{R} \ln 4$
3
JEE Main 2025 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1

Two identical symmetric double convex lenses of focal length f are cut into two equal parts L1, L2 by AB plane and L3, L4 by XY plane as shown in figure respectively. The ratio of focal lengths of lenses L1 and L3 is

JEE Main 2025 (Online) 29th January Evening Shift Physics - Geometrical Optics Question 6 English
A

1 : 2

B

1 : 1

C

2 : 1

D

1 : 4

4
JEE Main 2025 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1

A point charge causes an electric flux of $-2 \times 10^4 \mathrm{Nm}^2 \mathrm{C}^{-1}$ to pass through a spherical Gaussian surface of 8.0 cm radius, centred on the charge. The value of the point charge is :

(Given $\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )

A
$17.7 \times 10^{-8} \mathrm{C}$
B
$-17.7 \times 10^{-8} \mathrm{C}$
C
$15.7 \times 10^{-8} \mathrm{C}$
D
$-15.7 \times 10^{-8} \mathrm{C}$
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