1
JEE Main 2024 (Online) 9th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency '$$A$$' $$\times 10^{12}$$ hertz and that has a radiant intensity in that direction of $$\frac{1}{{ 'B'}}$$, watt per steradian. '$$A$$' and '$$B$$' are respectively

A
450 and 683
B
540 and $$\frac{1}{683}$$
C
540 and 683
D
450 and $$\frac{1}{683}$$
2
JEE Main 2024 (Online) 9th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match List I with List II

LIST I LIST II
A. Melting Point $$[\mathrm{K}]$$ I. $$\mathrm{T} 1>\mathrm{In}>\mathrm{Ga}>\mathrm{A} 1>\mathrm{B}$$
B. Ionic Radius $$[\mathrm{M}^{+3} / \mathrm{pm}]$$ II. $$\mathrm{B}>\mathrm{T} 1>\mathrm{Al} \approx \mathrm{Ga}>\mathrm{In}$$
C. $$\Delta_{\mathrm{i}} \mathrm{H}_1[\mathrm{~kJ} \mathrm{~mol}^{-1}]$$ III. $$\mathrm{T} 1>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}$$
D. Atomic Radius [pm] IV. $$\mathrm{B}>\mathrm{A} 1>\mathrm{T} 1>\mathrm{In}>\mathrm{Ga}$$

Choose the correct answer from the options given below:

A
A-IV, B-I, C-II, D-III
B
A-I, B-II, C-III, D-IV
C
A-III, B-IV, C-I, D-II
D
A-II, B-III, C-IV, D-I
3
JEE Main 2024 (Online) 9th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning :

A
$$\Lambda_{\mathrm{m}}-\Lambda_{\mathrm{m}}^{\circ}+\mathrm{AC}^{\frac{1}{2}}=0$$
B
$$\Lambda_{\mathrm{m}}^2 \mathrm{C}+\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}^2}-\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}} \Lambda_{\mathrm{m}}^{\circ}=0$$
C
$$\Lambda_{\mathrm{m}}-\Lambda_{\mathrm{m}}^{\circ}-\mathrm{AC}^{\frac{1}{2}}=0$$
D
$$\Lambda_{\mathrm{m}}^2 \mathrm{C}-\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ 2}+\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}} \Lambda_{\mathrm{m}}^{\circ}=0$$
4
JEE Main 2024 (Online) 9th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

The correct increasing order for bond angles among $$\mathrm{BF}_3, \mathrm{PF}_3$$ and $$\mathrm{ClF}_3$$ is :

A
$$\mathrm{BF}_3=\mathrm{PF}_3<\mathrm{ClF}_3$$
B
$$\mathrm{BF}_3<\mathrm{PF}_3<\mathrm{ClF}_3$$
C
$$\mathrm{ClF}_3<\mathrm{PF}_3<\mathrm{BF}_3$$
D
$$\mathrm{PF}_3<\mathrm{BF}_3<\mathrm{ClF}_3$$
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