1
JEE Main 2023 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
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For the reaction

JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Haloalkanes and Haloarenes Question 45 English

The correct statement is

A
The solvent used in the reaction solvates the ions formed in rate determining step.
B
Br$$^-$$ can act as competing nucleophile.
C
The reaction can occur in acetic acid also.
D
The transition state formed in the above reaction is less polar than the localised anion.
2
JEE Main 2023 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The major products A and B from the following reactions are:

JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 53 English

A
JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 53 English Option 1
B
JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 53 English Option 2
C
JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 53 English Option 3
D
JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 53 English Option 4
3
JEE Main 2023 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which of the following options are correct for the reaction

$$2\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}(\mathrm{aq})+\mathrm{Zn}(\mathrm{s}) \rightarrow 2 \mathrm{Au}(\mathrm{s})+\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-}(\mathrm{aq})$$

A. Redox reaction

B. Displacement reaction

C. Decomposition reaction

D. Combination reaction

Choose the correct answer from the options given below:

A
A and B only
B
C and D only
C
A only
D
A and D only
4
JEE Main 2023 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For a concentrated solution of a weak electrolyte ($$\mathrm{K}_{\text {eq }}=$$ equilibrium constant) $$\mathrm{A}_{2} \mathrm{B}_{3}$$ of concentration '$$c$$', the degree of dissociation '$$\alpha$$' is :

A
$$\left(\frac{K_{e q}}{25 c^{2}}\right)^{\frac{1}{5}}$$
B
$$\left(\frac{K_{e q}}{108 c^{4}}\right)^{\frac{1}{5}}$$
C
$$\left(\frac{K_{e q}}{5 c^{4}}\right)^{\frac{1}{5}}$$
D
$$\left(\frac{K_{e q}}{6 c^{5}}\right)^{\frac{1}{5}}$$
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