1
JEE Main 2023 (Online) 11th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The magnetic moment is measured in Bohr Magneton (BM).

Spin only magnetic moment of $$\mathrm{Fe}$$ in $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$ and $$\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$$ complexes respectively is :

A
3.87 B.M. and 1.732 B.M.
B
5.92 B.M. and 1.732 B.M.
C
6.92 B.M. in both
D
4.89 B.M. and 6.92 B.M.
2
JEE Main 2023 (Online) 11th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R.

JEE Main 2023 (Online) 11th April Evening Shift Chemistry - Hydrocarbons Question 46 English

In the light of the above statements, choose the correct answer from the options given below:

A
Both A and R are true and R is the correct explanation of A
B
A is false but R is true
C
A is true but R is false
D
Both A and R are true but R is NOT the correct explanation of A
3
JEE Main 2023 (Online) 11th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For a chemical reaction $$\mathrm{A}+\mathrm{B} \rightarrow$$ Product, the order is 1 with respect to $$\mathrm{A}$$ and $$\mathrm{B}$$.

$$\mathrm{Rate}$$
$$\mathrm{mol~L^{-1}~S^{-1}}$$
$$\mathrm{[A]}$$
$$\mathrm{mol~L^{-1}}$$
$$\mathrm{[B]}$$
$$\mathrm{mol~L^{-1}}$$
0.10 20 0.5
0.40 $$x$$ 0.5
0.80 40 $$y$$

What is the value of $$x$$ and $$y$$ ?

A
80 and 4
B
160 and 4
C
80 and 2
D
40 and 4
4
JEE Main 2023 (Online) 11th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

JEE Main 2023 (Online) 11th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 41 English

Product [X] formed in the above reaction is :

A
JEE Main 2023 (Online) 11th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 41 English Option 1
B
JEE Main 2023 (Online) 11th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 41 English Option 2
C
$$\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$$
D
$$\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}$$
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