What weight of glucose must be dissolved in $$100 \mathrm{~g}$$ of water to lower the vapour pressure by $$0.20 \mathrm{~mm} ~\mathrm{Hg}$$ ?

(Assume dilute solution is being formed)

Given : Vapour pressure of pure water is $$54.2 \mathrm{~mm} ~\mathrm{Hg}$$ at room temperature. Molar mass of glucose is $$180 \mathrm{~g} \mathrm{~mol}^{-1}$$

A solution is prepared by adding $$2 \mathrm{~g}$$ of "$$\mathrm{X}$$" to 1 mole of water. Mass percent of "$$\mathrm{X}$$" in the solution is :

Compound from the following that will not produce precipitate on reaction with $$\mathrm{AgNO}_{3}$$ is :

The magnetic moment is measured in Bohr Magneton (BM).

Spin only magnetic moment of $$\mathrm{Fe}$$ in $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$ and $$\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$$ complexes respectively is :