1
JEE Main 2022 (Online) 28th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An infinitely long hollow conducting cylinder with radius R carries a uniform current along its surface.

Choose the correct representation of magnetic field (B) as a function of radial distance (r) from the axis of cylinder.

A
JEE Main 2022 (Online) 28th June Morning Shift Physics - Magnetic Effect of Current Question 85 English Option 1
B
JEE Main 2022 (Online) 28th June Morning Shift Physics - Magnetic Effect of Current Question 85 English Option 2
C
JEE Main 2022 (Online) 28th June Morning Shift Physics - Magnetic Effect of Current Question 85 English Option 3
D
JEE Main 2022 (Online) 28th June Morning Shift Physics - Magnetic Effect of Current Question 85 English Option 4
2
JEE Main 2022 (Online) 28th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A radar sends an electromagnetic signal of electric field (E0) = 2.25 V/m and magnetic field (B0) = 1.5 $$\times$$ 10$$-$$8 T which strikes a target on line of sight at a distance of 3 km in a medium. After that, a part of signal (echo) reflects back towards the radar with same velocity and by same path. If the signal was transmitted at time t = 0 from radar, then after how much time echo will reach to the radar?

A
2.0 $$\times$$ 10$$-$$5 s
B
4.0 $$\times$$ 10$$-$$5 s
C
1.0 $$\times$$ 10$$-$$5 s
D
8.0 $$\times$$ 10$$-$$5 s
3
JEE Main 2022 (Online) 28th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be -

A
180 $$-$$ 2A
B
90 $$-$$ A
C
180 + 2A
D
180 $$-$$ 3A
4
JEE Main 2022 (Online) 28th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 $$\mathop A\limits^o $$ is used to see th object will be :

A
8.1 $$\times$$ 106
B
10.0 $$\times$$ 107
C
8.2 $$\times$$ 105
D
1.0 $$\times$$ 10$$-$$8
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