1
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let y = y(x) be a solution of the differential equation,

$$\sqrt {1 - {x^2}} {{dy} \over {dx}} + \sqrt {1 - {y^2}} = 0$$, |x| < 1.

If $$y\left( {{1 \over 2}} \right) = {{\sqrt 3 } \over 2}$$, then $$y\left( { - {1 \over {\sqrt 2 }}} \right)$$ is equal to :
A
$$ - {{\sqrt 3 } \over 2}$$
B
None of those
C
$${{1 \over {\sqrt 2 }}}$$
D
$$-{{1 \over {\sqrt 2 }}}$$
2
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the equation, x2 + bx + 45 = 0 (b $$ \in $$ R) has conjugate complex roots and they satisfy |z +1| = 2$$\sqrt {10} $$ , then :
A
b2 – b = 42
B
b2 + b = 12
C
b2 + b = 72
D
b2 – b = 30
3
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The graph which depicts the results of Rutherford gold foil experiment with $$\alpha $$-particales is :
$$\theta $$ : Scattering angle
Y : Number of scattered $$\alpha $$-particles detected (Plots are schematic and not to scale)
A
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 216 English Option 1
B
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 216 English Option 2
C
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 216 English Option 3
D
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 216 English Option 4
4
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The critical angle of a medium for a specific wavelength, if the medium has relative permittivity 3 and relative permeability $${4 \over 3}$$ for this wavelength, will be :
A
45°
B
15°
C
30°
D
60°

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