1
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The shortest distance between the lines

$${{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}$$ and

$${{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}$$ is :
A
3
B
$${7 \over 2}\sqrt {30} $$
C
$$3\sqrt {30} $$
D
$$2\sqrt {30} $$
2
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If a, b and c are the greatest value of 19Cp, 20Cq and 21Cr respectively, then :
A
$${a \over {11}} = {b \over {22}} = {c \over {21}}$$
B
$${a \over {10}} = {b \over {22}} = {c \over {21}}$$
C
$${a \over {10}} = {b \over {11}} = {c \over {42}}$$
D
$${a \over {11}} = {b \over {22}} = {c \over {42}}$$
3
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let ƒ : R $$ \to $$ R be such that for all x $$ \in $$ R
(21+x + 21–x), ƒ(x) and (3x + 3–x) are in A.P.,
then the minimum value of ƒ(x) is
A
2
B
0
C
3
D
4
4
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The mean and the standard deviation (s.d.) of 10 observations are 20 and 2 resepectively. Each of these 10 observations is multiplied by p and then reduced by q, where p $$ \ne $$ 0 and q $$ \ne $$ 0. If the new mean and new s.d. become half of their original values, then q is equal to
A
10
B
-20
C
-10
D
-5

JEE Main Papers

All year-wise previous year question papers

2023
2021