1
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider a solid sphere of radius R and mass density
$$\rho \left( r \right) = {\rho _0}\left( {1 - {{{r^2}} \over {{R^2}}}} \right)$$ , $$0 < r \le R$$
The minimum density of a liquid in which it will float is :
A
$${{2{\rho _0}} \over 3}$$
B
$${{2{\rho _0}} \over 5}$$
C
$${{{\rho _0}} \over 5}$$
D
$${{{\rho _0}} \over 3}$$
2
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In finding the electric field using Gauss Law the formula $$\left| {\overrightarrow E } \right| = {{{q_{enc}}} \over {{\varepsilon _0}\left| A \right|}}$$ is applicable. In the formula $${{\varepsilon _0}}$$ is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
A
Only when $$\left| {\overrightarrow E } \right|$$ = constant on the surface.
B
For any choice of Gaussian surface.
C
Only when the Gaussian surface is an equipotential surface.
D
Only when the Gaussian surface is an equipotential surface and $$\left| {\overrightarrow E } \right|$$ is constant on the surface.
3
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The graph which depicts the results of Rutherford gold foil experiment with $$\alpha $$-particales is :
$$\theta $$ : Scattering angle
Y : Number of scattered $$\alpha $$-particles detected (Plots are schematic and not to scale)
A
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 172 English Option 1
B
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 172 English Option 2
C
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 172 English Option 3
D
JEE Main 2020 (Online) 8th January Morning Slot Physics - Atoms and Nuclei Question 172 English Option 4
4
JEE Main 2020 (Online) 8th January Morning Slot
Numerical
+4
-0
Change Language
A particle is moving along the x-axis with its coordinate with the time 't' given be
x(t) = 10 + 8t – 3t2. Another particle is moving the y-axis with its coordinate as a function of time given by y(t) = 5 – 8t3.
At t = 1s, the speed of the second particle as measured in the frame of the first particle is given as $$\sqrt v $$. Then v (in m/s) is ______.
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