1
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product in the following conversion is –

JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 135 English
A
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 135 English Option 1
B
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 135 English Option 2
C
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 135 English Option 3
D
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 135 English Option 4
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is –

JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 119 English
A
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 119 English Option 1
B
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 119 English Option 2
C
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 119 English Option 3
D
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 119 English Option 4
3
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
$$ \wedge _m^ \circ $$ for NaCl, HCl and NaA are 126.4, 425.9 and 100.5 S cm2 mol–1, respectively. If the conductivity of 0.001 M HA is-

5 $$ \times $$ 10–5 S cm–1, degree of dissociation of HA is -
A
0.50
B
0.125
C
0.25
D
0.75
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The integral $$\int\limits_1^e {\left\{ {{{\left( {{x \over e}} \right)}^{2x}} - {{\left( {{e \over x}} \right)}^x}} \right\}} \,$$ loge x dx is equal to :
A
$$ - {1 \over 2} + {1 \over e} - {1 \over {2{e^2}}}$$
B
$${3 \over 2} - e - {1 \over {2{e^2}}}$$
C
$${1 \over 2} - e - {1 \over {{e^2}}}$$
D
$${3 \over 2} - {1 \over e} - {1 \over {2{x^2}}}$$
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