1
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The element that does NOT show catenation is :
A
Ge
B
Si
C
Sn
D
Pb
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The aldehydes which will not form Grignard product with one equivalent Grignard reagents are -

JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 172 English
A
B and D
B
C and D
C
B, C and D
D
B and C
3
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 $$\pi $$a0 (a0 is Bohr radius), then the value of n/z is -
A
0.75
B
0.40
C
1.50
D
1.0
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

(i)  C (graphite) + O2(g) $$ \to $$ CO2(g); $$\Delta $$rH$$^\Theta $$ = x kJ mol$$-$$1

(ii)  C(graphite) + $${1 \over 2}$$O2(g) $$ \to $$ CO(g); $$\Delta $$rH$$^\Theta $$ = y kJ mol$$-$$1

(iii)  CO(g) + $${1 \over 2}$$ O2(g) $$ \to $$ CO2(g); $$\Delta $$rH$$^\Theta $$ = z kJ mol$$-$$1

Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
A
z = x + y
B
x = y + z
C
x = y – z
D
y = 2z – x
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