1
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
8 g of NaOH is dissolved in 18g of H2O. Mole fraction of NaOH in solution and molality (in mol kg–1) of the solution respectively are -
A
0.2, 11.11
B
0.167, 22.20
C
0.167, 11.11
D
0.2, 22.20
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The upper stratosphere consisting of the ozone layer protects us from sun's radiation that falls in the wavelength region of -
A
200-315 nm
B
400-550 nm
C
0.8-1.5 nm
D
600-750 nm
3
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

(i)  C (graphite) + O2(g) $$ \to $$ CO2(g); $$\Delta $$rH$$^\Theta $$ = x kJ mol$$-$$1

(ii)  C(graphite) + $${1 \over 2}$$O2(g) $$ \to $$ CO(g); $$\Delta $$rH$$^\Theta $$ = y kJ mol$$-$$1

(iii)  CO(g) + $${1 \over 2}$$ O2(g) $$ \to $$ CO2(g); $$\Delta $$rH$$^\Theta $$ = z kJ mol$$-$$1

Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
A
z = x + y
B
x = y + z
C
x = y – z
D
y = 2z – x
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 $$\pi $$a0 (a0 is Bohr radius), then the value of n/z is -
A
0.75
B
0.40
C
1.50
D
1.0
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