1
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The moment of inertia of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is 'I(x)'. Which one of the graphs represents the variation of I(x) with x correctly ?
A
JEE Main 2019 (Online) 12th January Evening Slot Physics - Rotational Motion Question 150 English Option 1
B
JEE Main 2019 (Online) 12th January Evening Slot Physics - Rotational Motion Question 150 English Option 2
C
JEE Main 2019 (Online) 12th January Evening Slot Physics - Rotational Motion Question 150 English Option 3
D
JEE Main 2019 (Online) 12th January Evening Slot Physics - Rotational Motion Question 150 English Option 4
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6, respectively, are :

JEE Main 2019 (Online) 12th January Evening Slot Physics - Current Electricity Question 240 English
A
1.1 A, – 0.4 A, 0.4 A
B
$$-$$ 0.4 A, 0.4 A, 1.1 A
C
0.4 A, 1.1 A, 0.4 A
D
1.1 A, 0.4 A, 0.4 A
3
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A load of mass M kg is suspended from a steel wire of length 2m and radius 1.0 mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 mm. Now the load is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8.

The new value of increase in length of the steel wire is:
A
5.0 mm
B
zero
C
3.0 mm
D
4.0 mm
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A parallel plate capacitor with plates of area 1 m2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate is :

(Take $$\varepsilon $$0 = 8.85 $$ \times $$ 10$$-$$12 $${{{C^2}} \over {N - {m^2}}}$$)
A
9.85 $$ \times $$ 10–10 C
B
8.85 $$ \times $$ 10–10 C
C
6.85 $$ \times $$ 10–10 C
D
7.85 × 10–10 C
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