1
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
$$\mathop {\lim }\limits_{x \to 0} {{x\cot \left( {4x} \right)} \over {{{\sin }^2}x{{\cot }^2}\left( {2x} \right)}}$$ is equal to :
A
0
B
4
C
1
D
2
2
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If  $$\left| {\matrix{ {a - b - c} & {2a} & {2a} \cr {2b} & {b - c - a} & {2b} \cr {2c} & {2c} & {c - a - b} \cr } } \right|$$

      = (a + b + c) (x + a + b + c)2, x $$ \ne $$ 0,

then x is equal to :
A
–2(a + b + c)
B
2(a + b + c)
C
abc
D
–(a + b + c)
3
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\alpha $$ and $$\beta $$ be the roots of the quadratic equation x2 sin $$\theta $$ – x(sin $$\theta $$ cos $$\theta $$ + 1) + cos $$\theta $$ = 0 (0 < $$\theta $$ < 45o), and $$\alpha $$ < $$\beta $$. Then $$\sum\limits_{n = 0}^\infty {\left( {{\alpha ^n} + {{{{\left( { - 1} \right)}^n}} \over {{\beta ^n}}}} \right)} $$ is equal to :
A
$${1 \over {1 + \cos \theta }} + {1 \over {1 - \sin \theta }}$$
B
$${1 \over {1 - \cos \theta }} + {1 \over {1 + \sin \theta }}$$
C
$${1 \over {1 - \cos \theta }} - {1 \over {1 + \sin \theta }}$$
D
$${1 \over {1 + \cos \theta }} - {1 \over {1 - \sin \theta }}$$
4
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let z be a complex number such that |z| + z = 3 + i (where i = $$\sqrt { - 1} $$). Then |z| is equal to :
A
$${{\sqrt {34} } \over 3}$$
B
$${5 \over 3}$$
C
$${5 \over 4}$$
D
$${{\sqrt {41} } \over 4}$$
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