1
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let a1, a2, a3,......be an A.P. with a6 = 2. Then the common difference of this A.P., which maximises the product a1a4a5, is :
A
$${3 \over 2}$$
B
$${6 \over 5}$$
C
$${8 \over 5}$$
D
$${2 \over 3}$$
2
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The negation of the Boolean expression ~ s $$ \vee $$ (~r $$ \wedge $$ s) is equivalent to :
A
~ s $$ \wedge $$ ~ r
B
r
C
s $$ \vee $$ r
D
s $$ \wedge $$ r
3
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $${\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alpha $$,where –1 $$ \le $$ x $$ \le $$ 1, – 2 $$ \le $$ y $$ \le $$ 2, x $$ \le $$ $${y \over 2}$$ , then for all x, y, 4x2 – 4xy cos $$\alpha $$ + y2 is equal to :
A
4 sin2 $$\alpha $$
B
2 sin2 $$\alpha $$
C
4 sin2 $$\alpha $$ - 2x2y2
D
4 cos2 $$\alpha $$ + 2x2y2
4
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
If the tangent to the curve $$y = {x \over {{x^2} - 3}}$$ , $$x \in \rho ,\left( {x \ne \pm \sqrt 3 } \right)$$, at a point ($$\alpha $$, $$\beta $$) $$ \ne $$ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :
A
| 6$$\alpha $$ + 2$$\beta $$ | = 9
B
| 2$$\alpha $$ + 6$$\beta $$ | = 11
C
| 2$$\alpha $$ + 6$$\beta $$ | = 19
D
| 6$$\alpha $$ + 2$$\beta $$ | = 19
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