1
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :
A
25 : 9
B
4 : 1
C
$${\left( {\sqrt 3 + 1} \right)^4}:16$$
D
9 : 1
2
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet?

[Given ; Mass of planet = 8 × 1022 kg, Radius of planet = 2 × 106 m, Gravitational constant G = 6.67 × 10–11 Nm2 /kg2]
A
13
B
9
C
17
D
11
3
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
When heat Q is supplied to a diatomic gas of rigid molecules, at constant volume its temperature increases by $$\Delta $$T. the heat required to produce the same change in temperature, at a constant pressure is :
A
$${7 \over 5}Q$$
B
$${3 \over 2}Q$$
C
$${2 \over 3}Q$$
D
$${5 \over 3}Q$$
4
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The magnitude of the magnetic field at the centre of an equilateral triangular loop of side 1 m which is carrying a current of 10 A is :
[Take $$\mu $$0 = 4$$\pi $$ × 10–7 NA–2]
A
3 $$\mu $$T
B
18 $$\mu $$T
C
9 $$\mu $$T
D
1 $$\mu $$T

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