1
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet?

[Given ; Mass of planet = 8 × 1022 kg, Radius of planet = 2 × 106 m, Gravitational constant G = 6.67 × 10–11 Nm2 /kg2]
A
13
B
9
C
17
D
11
2
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :
A
25 : 9
B
4 : 1
C
$${\left( {\sqrt 3 + 1} \right)^4}:16$$
D
9 : 1
3
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct figure that shows, schematically, the wave pattern produced by superposition of two waves of frequencies 9 Hz and 11 Hz, is :
A
JEE Main 2019 (Online) 10th April Evening Slot Physics - Waves Question 84 English Option 1
B
JEE Main 2019 (Online) 10th April Evening Slot Physics - Waves Question 84 English Option 2
C
JEE Main 2019 (Online) 10th April Evening Slot Physics - Waves Question 84 English Option 3
D
JEE Main 2019 (Online) 10th April Evening Slot Physics - Waves Question 84 English Option 4
4
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In an experiment, brass and steel wires of length 1 m each with areas of cross section 1mm2 are used. The wires are connected in series and one end of the combined wire is connected to a rigid support and other end is subjected to elongation. The stress required to produce a net elongation of 0.2 mm is, [Given, the Young's Modulus for steel and brass are, respectively, 120 × 109 N/m2 and 60 × 109 N/m2]
A
8.0 × 106 N/m2
B
1.2 × 106 N/m2
C
0.2 × 106 N/m2
D
1.8 × 106 N/m2
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