1
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The increasing order of nucleophilicity of the following nucleophiles is :
(a) CH3CO2$$-$$           (b) H2O
(c) CH3SO3$$-$$           (d) $$\mathop O\limits^ - H$$
A
(b) < (c) < (a) < (d)
B
(b) < (c) < (d) < (a)
C
(a) < (d) < (c) < (b)
D
(d) < (a) < (c) < (b)
2
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product 'Y' in the following reaction is : JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 160 English
A
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 160 English Option 1
B
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 160 English Option 2
C
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 160 English Option 3
D
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 160 English Option 4
3
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Which one of the following graphs between molar conductivity ($${\Lambda _m}$$) versus $$\sqrt C $$ is correct ?
A
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Electrochemistry Question 122 English Option 1
B
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Electrochemistry Question 122 English Option 2
C
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Electrochemistry Question 122 English Option 3
D
JEE Main 2019 (Online) 10th April Evening Slot Chemistry - Electrochemistry Question 122 English Option 4
4
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The crystal field stabilization energy (CFSE) of [Fe(H2O)6]Cl2 and K2[NiCl4] respectively, are :
A
– 0.4 $$\Delta $$0 and – 0.8 $$\Delta $$t
B
– 0.6 $$\Delta $$0 and – 0.8 $$\Delta $$t
C
– 2.4 $$\Delta $$0 and – 1.2 $$\Delta $$t
D
– 0.4 $$\Delta $$0 and – 1.2 $$\Delta $$t
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