1
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Moment of inertia of an equilateral triangular lamina ABC, about the axis passing through its centre O and perpendicular to its plane is Io as shown in the figure. A cavity DEF is cut out from the lamina, where D, E, F are the mid points of the sides. Moment of inertia of the remaining part of lamina about the same axis is :

JEE Main 2017 (Online) 8th April Morning Slot Physics - Rotational Motion Question 185 English
A
$${7 \over 8}$$ Io
B
$${15 \over 16}$$ Io
C
$${{3\,{{\rm I}_o}} \over 4}$$
D
$${{31\,{{\rm I}_o}} \over 32}$$
2
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to an 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block is :
A
$${1 \over 4}Hz$$
B
$${1 \over {2\sqrt 2 }}Hz$$
C
$${1 \over 2}Hz$$
D
$$2$$ $$Hz$$
3
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity ?
A
JEE Main 2017 (Online) 8th April Morning Slot Physics - Motion in a Straight Line Question 91 English Option 1
B
JEE Main 2017 (Online) 8th April Morning Slot Physics - Motion in a Straight Line Question 91 English Option 2
C
JEE Main 2017 (Online) 8th April Morning Slot Physics - Motion in a Straight Line Question 91 English Option 3
D
JEE Main 2017 (Online) 8th April Morning Slot Physics - Motion in a Straight Line Question 91 English Option 4
4
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Time (T), velocity (C) and angular momentum (h) are chosen as fundamentalquantities instead of mass, length and time. In terms of these, the dimensions of mass would be :
A
[M] = [T$$-$$1 C$$-$$2 h]
B
[M] = [T$$-$$1 C2 h]
C
[M] = [T$$-$$1 C$$-$$2 h$$-$$1]
D
[M] = [T C$$-$$2 h]
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