1
JEE Main 2016 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of $$\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)$$ is equal to :
A
560
B
680
C
1240
D
1085
2
JEE Main 2016 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If P = $$\left[ {\matrix{ {{{\sqrt 3 } \over 2}} & {{1 \over 2}} \cr { - {1 \over 2}} & {{{\sqrt 3 } \over 2}} \cr } } \right],A = \left[ {\matrix{ 1 & 1 \cr 0 & 1 \cr } } \right]\,\,\,$$

Q = PAPT, then PT Q2015 P is :
A
$$\left[ {\matrix{ 0 & {2015} \cr 0 & 0 \cr } } \right]$$
B
$$\left[ {\matrix{ {2015} & 1 \cr 0 & {2015} \cr } } \right]$$
C
$$\left[ {\matrix{ {2015} & 0 \cr 1 & {2015} \cr } } \right]$$
D
$$\left[ {\matrix{ 1 & {2015} \cr 0 & 1 \cr } } \right]$$
3
JEE Main 2016 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The point (2, 1) is translated parallel to the line L : x− y = 4 by $$2\sqrt 3 $$ units. If the newpoint Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is :
A
x + y = 2 $$-$$ $$\sqrt 6 $$
B
x + y = 3 $$-$$ 3$$\sqrt 6 $$
C
x + y = 3 $$-$$ 2$$\sqrt 6 $$
D
2x + 2y = 1 $$-$$ $$\sqrt 6 $$
4
JEE Main 2016 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If a variable line drawn through the intersection of the lines $${x \over 3} + {y \over 4} = 1$$ and $${x \over 4} + {y \over 3} = 1,$$ meets the coordinate axes at A and B, (A $$ \ne $$ B), then the locus of the midpoint of AB is :
A
6xy = 7(x + y)
B
4(x + y)2 − 28(x + y) + 49 = 0
C
7xy = 6(x + y)
D
14(x + y)2 − 97(x + y) + 168 = 0

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