NaBH4 reduces both ketone into alcohol and imine into 2o amine but it can't reduce alkene as the reacting species of NaBH4 is H- which can't attack as a nucleophile to alkene as alkene itself is a nucleophile.
MCQ (Single Correct Answer)
JEE Main 2019 (Online) 10th January Evening Slot
What will be the major product in the following mononitration reaction ?
Here in the compound $$\pi $$ bond of C = O bond will be at resonance with benzene ring with -M effect. But lone pair of N atom is electron donating group which will make the left benzene ring more active by +M effect than right benzene ring and
hence electrophilic substitution reaction will be taken place at
ortho- or para- position of left benzene ring. As ortho-product formed is sterically
hindered and hence para-product will be major product.
Questions Asked from Aldehydes, Ketones and Carboxylic Acids
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